[magick-users] Reducing output range

[Gabe Schaffer]

On 1/19/07, Illtud Daniel <illtud.daniel at llgc.org.uk> wrote:

> However, If I do:
>
> $image->Fx(expression=>'r/8');
>
> In my perl, it makes no change to the image at all. Where am I going
> wrong?

The Fx operator does not change the image; it returns a new one. This
will do what you want:

$newimage = $image->Fx(expression=>'r/8');

Note that the Evaluate operator is going to be much faster, so don't
worry about Fx.

GNS